oracle中使用SQL递归语句
发布时间：2010/9/1 11:04:43 来源：城市学习网 编辑：ziteng
例子：
pid id
a b
a c
a e
b b1
b b2
c c1
e e1
e e3
d d1
指定pid=a，选出
a b
a c
a e
b b1
b b2
c c1
e e1
e e3
SQL语句：select parent,child from test start with pid='a'
connect by prior id=pid
Oracle SQL的递归查询：
1、表机构
SQL> desc comm_org_subjection
Name Null? Type
----------------------------------------- -------- ----------------------------
ORG_SUBJECTION_ID NOT NULL VARCHAR2(32) 子键
ORG_ID NOT NULL VARCHAR2(32)
FATHER_ORG_ID NOT NULL VARCHAR2(32) 父键
LOCKED_IF NOT NULL VARCHAR2(1)
START_DATE NOT NULL DATE
END_DATE DATE
EDITION_NAMEPLATE NUMBER(8)
CODE_AFFORD_IF VARCHAR2(1)
CODE_AFFORD_ORG_ID NOT NULL VARCHAR2(32)
CODING_SHOW_ID NUMBER(8)
BSFLAG VARCHAR2(1)
MODIFI_DATE DATE
CREATOR_ID VARCHAR2(32)
CREATE_DATE DATE
CREATOR VARCHAR2(35)
2、递归查找父结点 org_id为C6000000000001下的所有子结点:
select * from comm_org_subjection a
start with a.org_id='C6000000000001'
connect by prior a.org_subjection_id=a.father_org_id
3、递归查找子结点 org_id为C6000000000001下的所有父结点:
select org_id from comm_org_subjection a
start with a.org_id='C6000000000001'
connect by prior a.father_org_id=a.org_subjection_id
